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Maharashtra State BoardSSC (English Medium) 9th Standard

The calculated mean of 50 observations was 80. It was later discovered that observation 19 was recorded by mistake as 91. What was the correct mean?

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Question

The calculated mean of 50 observations was 80. It was later discovered that observation 19 was recorded by mistake as 91. What was the correct mean?

Sum
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Solution

Mean = `"The sum of all observations"/"Total number of observations"`

∴ The sum of all observations = Mean x Total number of observations 

∴ The sum of 50 observations = 80 x 50

= 4000

Sum of observations after correction = 4000 + 19 – 91

= 3928 

∴ Corrected mean = `"Sum of observations after correction"/"Total number of observations"`

= `3928/50`

 = 78.56

∴ The corrected mean is 78.56.

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Chapter 7: Statistics - Practice set 7.5 [Page 125]

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Balbharati Mathematics 1 [English] Standard 9 Maharashtra State Board
Chapter 7 Statistics
Practice set 7.5 | Q (7) | Page 125

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