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Question
The areas of two similar triangles are 121 cm2 and 100 cm2. If the altitude of a larger triangle is 6.6 cm, then the corresponding altitude of the smaller triangle is ______.
Options
5.5 cm
5 cm
6 cm
4.4 cm
MCQ
Fill in the Blanks
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Solution
The areas of two similar triangles are 121 cm2 and 100 cm2. If the altitude of a larger triangle is 6.6 cm, then the corresponding altitude of the smaller triangle is 6 cm.
Explanation:
For similar triangles, the ratio of areas is equal to the square of the ratio of corresponding sides (or altitudes):
`"Area"_1/"Area"_2 = (h_1/h_2)^2`
Let the larger triangle area = 121, the smaller = 100, and the altitude of the larger = 6.6 cm.
`121/100 = (6.6/h)^2`
`6.6/h = sqrt(121/100)`
`6.6/h = 11/10`
`h = 6.6 xx 10/11`
∴ h = 6 cm
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