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The areas of two similar triangles are 121 cm2 and 100 cm2. If the altitude of a larger triangle is 6.6 cm, then the corresponding altitude of the smaller triangle is ______. - Mathematics

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Question

The areas of two similar triangles are 121 cm2 and 100 cm2. If the altitude of a larger triangle is 6.6 cm, then the corresponding altitude of the smaller triangle is ______.

Options

  • 5.5 cm

  • 5 cm

  • 6 cm

  • 4.4 cm

MCQ
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Solution

The areas of two similar triangles are 121 cm2 and 100 cm2. If the altitude of a larger triangle is 6.6 cm, then the corresponding altitude of the smaller triangle is 6 cm.

Explanation:

For similar triangles, the ratio of areas is equal to the square of the ratio of corresponding sides (or altitudes):

`"Area"_1/"Area"_2 = (h_1/h_2)^2`

Let the larger triangle area = 121, the smaller = 100, and the altitude of the larger = 6.6 cm.

`121/100 = (6.6/h)^2`

`6.6/h = sqrt(121/100)`

`6.6/h = 11/10`

`h = 6.6 xx 10/11`

∴ h = 6 cm

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Chapter 13: Similarity - Exercise 13D [Page 291]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 13 Similarity
Exercise 13D | Q 10. | Page 291
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