Advertisements
Advertisements
Question
The area of the region bounded by the curve x = 2y + 3 and the y lines. y = 1 and y = –1 is ______.
Options
4 sq.units
`3/2` sq units
6 sq.units
8 sq.units
Advertisements
Solution
The area of the region bounded by the curve x = 2y + 3 and the y lines. y = 1 and y = –1 is 6 sq.units.
Explanation:
Given equations of lines are x = 2y + 3, y = 1 and y = –1

Required area = `int_-1^1 (2y + 3) "d"y`
= `2 * 1/2 [y^2]_-1^1 + 3[y]_-1^1`
= `(1 - 1) + 3(1 + 1)`
= 6 sq.units
APPEARS IN
RELATED QUESTIONS
Find the area bounded by the curve y = sin x between x = 0 and x = 2π.
Using integration, find the area of the region bounded between the line x = 2 and the parabola y2 = 8x.
Using integration, find the area of the region bounded by the line y − 1 = x, the x − axis and the ordinates x= −2 and x = 3.
Sketch the graph y = | x − 5 |. Evaluate \[\int\limits_0^1 \left| x - 5 \right| dx\]. What does this value of the integral represent on the graph.
Sketch the graph y = |x + 1|. Evaluate\[\int\limits_{- 4}^2 \left| x + 1 \right| dx\]. What does the value of this integral represent on the graph?
Find the area of the region bounded by x2 = 4ay and its latusrectum.
Find the area bounded by the curve y = 4 − x2 and the lines y = 0, y = 3.
Using integration, find the area of the region bounded by the triangle whose vertices are (2, 1), (3, 4) and (5, 2).
Find the area of the region common to the circle x2 + y2 = 16 and the parabola y2 = 6x.
Using integration, find the area of the region bounded by the triangle whose vertices are (−1, 2), (1, 5) and (3, 4).
Find the area of the region in the first quadrant enclosed by x-axis, the line y = \[\sqrt{3}x\] and the circle x2 + y2 = 16.
Make a sketch of the region {(x, y) : 0 ≤ y ≤ x2 + 3; 0 ≤ y ≤ 2x + 3; 0 ≤ x ≤ 3} and find its area using integration.
Find the area of the region {(x, y): x2 + y2 ≤ 4, x + y ≥ 2}.
Using integration, find the area of the following region: \[\left\{ \left( x, y \right) : \frac{x^2}{9} + \frac{y^2}{4} \leq 1 \leq \frac{x}{3} + \frac{y}{2} \right\}\]
Find the area bounded by the parabola x = 8 + 2y − y2; the y-axis and the lines y = −1 and y = 3.
Find the area bounded by the parabola y2 = 4x and the line y = 2x − 4 By using horizontal strips.
The area bounded by the parabola x = 4 − y2 and y-axis, in square units, is ____________ .
The area bounded by the curve y = x |x| and the ordinates x = −1 and x = 1 is given by
Find the area bounded by the parabola y2 = 4x and the line y = 2x − 4 By using vertical strips.
Find the area of the region bounded by the parabolas y2 = 6x and x2 = 6y.
The area of the region bounded by the curve y = x2 and the line y = 16 ______.
The area of the region bounded by the curve y = x2 + x, x-axis and the line x = 2 and x = 5 is equal to ______.
Find the area of the region bounded by the curves y2 = 9x, y = 3x
Find the area of the region enclosed by the parabola x2 = y and the line y = x + 2
Find the area bounded by the curve y = sinx between x = 0 and x = 2π.
Draw a rough sketch of the given curve y = 1 + |x +1|, x = –3, x = 3, y = 0 and find the area of the region bounded by them, using integration.
The area of the region bounded by the curve x2 = 4y and the straight line x = 4y – 2 is ______.
The area of the region bounded by parabola y2 = x and the straight line 2y = x is ______.
The area of the region bounded by the circle x2 + y2 = 1 is ______.
The area of the region bounded by the curve y = x + 1 and the lines x = 2 and x = 3 is ______.
The curve x = t2 + t + 1,y = t2 – t + 1 represents
Area of the region bounded by the curve y = |x + 1| + 1, x = –3, x = 3 and y = 0 is
The area of the region enclosed by the parabola x2 = y, the line y = x + 2 and the x-axis, is
Find the area of the region bounded by the curve `y = x^2 + 2, y = x, x = 0` and `x = 3`
The area enclosed by y2 = 8x and y = `sqrt(2x)` that lies outside the triangle formed by y = `sqrt(2x)`, x = 1, y = `2sqrt(2)`, is equal to ______.
Sketch the region bounded by the lines 2x + y = 8, y = 2, y = 4 and the Y-axis. Hence, obtain its area using integration.
Hence find the area bounded by the curve, y = x |x| and the coordinates x = −1 and x = 1.
