Advertisements
Advertisements
Question
The area of the minor segment of angle θ° of a circle of radius r is ______.
Fill in the Blanks
Advertisements
Solution
The area of the minor segment of angle θ° of a circle of radius r is `underlinebb(θ/360 xx πr^2 - r^2 sin θ/2 cos θ/2)`.
Explanation:
Area(segment) = Area(sector) – Area(Δ formed by the radii and chord)
= `(πθ)/360 r^2 - r^2·sin θ/2 cos θ/2`
shaalaa.com
Is there an error in this question or solution?
