Question

The angle of elevation of the top of a vertical cliff from a point 30 m away from the foot of the cliff is 60°. Find the height of the cliff. 

Answer 1

Let AB be the diff and angle of elevation from point C (on ground) is 30 °. 
In ΔABC

`("AB")/("BC") = tan60^circ`

`"AB"/30 = sqrt(3)`

AB = `30sqrt(3)` m

So , height of tower is `30sqrt(3)` m