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The algebraic form of Gauss's Law is represented as:

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Question

The algebraic form of Gauss's Law is represented as:

Options

  • \[\Phi_E = Q_{enc} \times \varepsilon_0\]

  • \[\oint \vec{E} \cdot d\vec{S} = Q_{enc}\]

  • \[\Phi_E = \frac{Q_{enc}}{\varepsilon_0}\]

  • \[E = \frac{Q_{enc}}{\varepsilon_0}\]

MCQ
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Solution

The algebraic form of Gauss's Law states that the electric flux ΦE through a closed surface equals the enclosed charge divided by the permittivity of free space (ε₀). This is one of three equivalent forms of expressing Gauss's Law, the other being verbal and integral forms.

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