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The ages of two brothers are 10 years and 14 years. In how many years time will the product of their ages be 285? - Mathematics

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Question

The ages of two brothers are 10 years and 14 years. In how many years time will the product of their ages be 285?

Sum
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Solution

Let the required time be x years.

Younger brother’s age = 10 + x

Elder brother’s age = 14 + x

Given that the product of their ages will be 285:

(10 + x) (14 + x) = 285

x2 + 24x + 140 = 285

x2 + 24x − 145 = 0

(x + 29) (x − 5) = 0

x = −29 or x = 5

Reject the negative value.

The product of their ages will be 285 after 5​ years.

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Chapter 5: Quadratic equations - Exercise 5E [Page 92]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 5 Quadratic equations
Exercise 5E | Q 38. | Page 92
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