Question

The 4^th term from the end of the AP: –11, –8, –5, ..., 49 is ______.

Options

• 37

• 40

• 43

• 58

Answer 1

The 4^th term from the end of the AP: –11, –8, –5, ..., 49 is 40.

Explanation:

We know that, the n^th term of an AP from the end is 

a_n = l – (n – 1)d   ...(i)

Here, l = Last term and l = 49  ...[Given]

Common difference,   

d = – 8 – (– 11)

= – 8 + 11

= 3

From equation (i),

a₄ = 49 – (4 – 1)3

= 49 – 9

= 40