Test the divisibility of 10001001 by 3.

Sum

10001001 by 3
10001001 is divisible by 3.
It is because the sum of its digits, 1 + 0 + 0 + 0 + 1 + 0 + 0 + 1, is 3, which is divisible by 3.

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Chapter 2: Factors and Multiples - Exercise 2B [Page 30]

Chapter 2 Factors and Multiples
Exercise 2B | Q 14.4 | Page 30

Test the divisibility of the following number by 3:
20701

Test the divisibility of the following numbers by 8:

9364

Test the divisibility of the following numbers by 9:

2358

In the following number, replace * by the smallest number to make it divisible by 3:

6*1054

In the following number, replace * by the smallest number to make it divisible by 11:

39*43

Test the divisibility of 1000001 by 11.

Give an example of a number which is divisible by both 2 and 8 but not by 16.

Write (T) for true and (F) for false against the following statement:

If a number is divisible by 4, it must be divisible by 8.

Find the greatest number which divides 2011 and 2623, leaving remainders 9 and 5 respectively.

Which of the following numbers is divisible by 4?