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Test the divisibility of 1000001 by 11.

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Question

Test the divisibility of 1000001 by 11.

Sum
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Solution

10000001 by 11
10000001 is divisible by 11.
Sum of digits at odd places = (1 + 0 + 0 + 0) = 1
Sum of digits at even places = (0 + 0 + 0 + 1) = 1
Difference of the two sums = (1 − 1) = 0, which is divisible by 11.

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Chapter 2: Factors and Multiples - Exercise 2B [Page 30]

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R.S. Aggarwal Mathematics [English] Class 6
Chapter 2 Factors and Multiples
Exercise 2B | Q 14.1 | Page 30
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