Question

Substituting \[V=\frac{Qd}{\varepsilon_0 A}\] into \[C=\frac{Q}{V}\] gives which capacitance?

Options

• \[C=\frac{d}{\varepsilon_0 A}\]

• \[C=\frac{\varepsilon_0 A}{d}\]

• \[C=\frac{\varepsilon_0 d}{A}\]

• \[C=\frac{Qd}{\varepsilon_0 A}\]

Answer 1

Using \[C=\frac{Q}{V}\] and substituting the potential difference cancels the charge \[Q\]. The result is \[C=\frac{\varepsilon_0 A}{d}\].