Advertisements
Advertisements
Question
State the laws of the simple pendulum?
Advertisements
Solution
- Law of length: For a given value of acceleration due to gravity, the time period of a simple pendulum is directly proportional to the square root of the length of the pendulum.
`"T" ∝ sqrt"l"` - Law of acceleration: For a fixed length, the time period of a simple pendulum is inversely proportional to the square root of acceleration due to gravity.
`"T" ∝ 1/sqrt"g"` - The period of a simple pendulum is independent of its mass.
- A simple pendulum's period is independent of its amplitude (for small amplitudes).
APPEARS IN
RELATED QUESTIONS
State the differential equation of linear simple harmonic motion.
A particle executing simple harmonic motion comes to rest at the extreme positions. Is the resultant force on the particle zero at these positions according to Newton's first law?
The motion of a particle is given by x = A sin ωt + B cos ωt. The motion of the particle is
A pendulum clock keeping correct time is taken to high altitudes,
The pendulum of a certain clock has time period 2.04 s. How fast or slow does the clock run during 24 hours?
A simple pendulum fixed in a car has a time period of 4 seconds when the car is moving uniformly on a horizontal road. When the accelerator is pressed, the time period changes to 3.99 seconds. Making an approximate analysis, find the acceleration of the car.
Write short notes on two springs connected in parallel.
What is the ratio of maxmimum acceleration to the maximum velocity of a simple harmonic oscillator?
The velocities of a particle in SHM at positions x1 and x2 are v1 and v2 respectively, its time period will be ______.
If x = `5 sin (pi t + pi/3) m` represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are ______.
