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State Raoult’s law. - Chemistry

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Question

State Raoult’s law. 

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Solution 1

Raoult’s law states that the partial vapour pressure of any volatile component of a solution is equal to the vapour pressure of the pure component multiplied by its mole fraction in the solution. 

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Solution 2

For a solution of volatile liquids, the partial vapour pressure of each component in the solution at a particular temperature is equal to the product of the vapour pressure of the component in the pure state and its mole fraction in the solution.

Mathematically, for a binary solution:

\[\ce{P_A = P{^{\circ}_{A}}\chi_A}\] and 

\[\ce{P_B = P{^{\circ}_{B}}\chi_B}\]

The total vapour pressure is:

\[\ce{P_{total} = P_A + P_B = P{^{\circ}_{A}}\chi_A + P{^{\circ}_{B}}\chi_B}\]

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Notes

Students can refer to the provided solutions based on their preferred marks.

Vapour Pressure of Solutions of Liquids in Liquids
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Chapter 2: Solutions - Very short answer questions

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SCERT Maharashtra Chemistry [English] 12 Standard HSC
Chapter 2 Solutions
Very short answer questions | Q 5

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