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Question
State clearly how photoelectric equation is obtained using the photon pictu.re of electromagnetic radiation.
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Solution
Einstein’s photoelectric equation,
hv = Kmax + Φ
Where
h = Planck’s constant
v = frequency
`K_max = 1/2mv_max^2 = eV_0 ((V_max = \text { maximum velocity of emitted photoelectron} ),(V_0 = \text { Stopping potential}))`
Φ = Work function
According to Planck’s quantum theory, light radiations consist of small packets of energy. Einstein postulated that a photon of energy hv is absorbed by the electron of the metal surface, then the energy equal to Φ is used to liberate electron from the surface and rest of the energy hv − Φbecomes the kinetic energy of the electron.
∴ Energy of photon is,
E = hv
Where, h = Planck’s constant
v = frequency of light
The minimum energy required by the electron of a material to escape out of it, is work function ‘Φ’.
The additional energy acquired by the electron appears as the maximum kinetic energy ‘Kmax’ of the electron.
i.e.,
Kmax = hv − Φ
or, `hv = K_max +phi` Einstein's photoelectric equation
Kmax = eV0.
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