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Question
Split 207 into three parts such that these are in AP and the product of the two smaller parts is 4623.
Sum
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Solution
Let the three parts of the number 207 are (a – d), a and (a + d), which are in AP.
Now, by given condition,
⇒ Sum of these parts = 207
⇒ a – d + a + a + d = 207
⇒ 3a = 207
a = 69
Given that,
Product of the two smaller parts = 4623
⇒ a(a – d) = 4623
⇒ 69 . (69 – d) = 4623
⇒ 69 – d = 67
⇒ d = 69 – 67 = 2
So, first part = a – d = 69 – 2 = 67,
Second part = a = 69
And third part = a + d = 69 + 2 = 71
Hence, required three parts are 67, 69, 71.
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