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Solve: x2+5≤x3+6, where x is a positive odd integer

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Question

Solve:

`x/2 + 5 <= x/3 + 6`, where x is a positive odd integer

Sum
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Solution

`x/2 + 5 <= x/3 + 6`

`x/2 - x/3 <= 6 - 5`

`x/6 <= 1`

`x <= 6`

Since, x is a positive odd integer

∴ Solution set = {1, 3, 5}

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Chapter 4: Linear Inequations (In one variable) - Exercise 4 (B) [Page 50]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 4 Linear Inequations (In one variable)
Exercise 4 (B) | Q 26.(i) | Page 50
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