Question

Solve for x : `"x"/4 + 3 <= "x"/3 + 4` , where xis a negative odd number.

Answer 1

`"x"/4 + 3 <= "x"/3 + 4`

`("x" + 12)/4 <= ("x" + 12)/3`

3x + 36 ≤ 4x + 48

3x- 4x ≤ 48- 36

- x ≤ 12

x ≥ -12 

Solution set = { -11 -9 -7 -5 -3 - 1}