Advertisements
Advertisements
Question
Solve: x2 – 4ax + 4a2 – b2 = 0.
Sum
Advertisements
Solution
x2 – 4ax + 4a2 – b2 = 0
⇒ x2 – 4ax + (2a + b)(2a – b) = 0
⇒ x2 – [(2a + b) + (2a – b)]x + (2a + b)(2a – b) = 0
⇒ x2 – (2a + b)x – (2a – b)x + (2a + b)(2a – b) = 0
⇒ x[x – (2a + b)] – (2a – b)[x – (2a + b)] = 0
⇒ [x – (2a + b)][x – (2a – b)] = 0
⇒ x – (2a + b) = 0 or x – (2a – b) = 0
⇒ x = (2a + b) or x = (2a – b)
Hence, (2a + b) and (2a – b) are the roots of the given equation.
shaalaa.com
Is there an error in this question or solution?
