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Question
Solve: `("x + 1")/3 + ("x + 4")/5 = ("x - 4")/7`
Sum
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Solution
`("x + 1")/3 + ("x + 4")/5 = ("x - 4")/7`
`("x + 1")/3 + ("x + 4")/5 - ("x - 4")/7 = 0`
`(35(x + 1) + 21(x + 4) - 15(x - 4))/105 = 0`
35x + 35 + 21x + 84 - 15x + 60 = 0
41x + 179 = 0
41x = -179
x = `(-179)/41`
x = -4`15/41`
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