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Question
Solve the inequation given below. Write the solution set and represent it on the number line:
`- 8 1/2 < - 1/2 - 4x ≤ 7 1/2, x ∈ I`
Sum
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Solution
Given,
⇒ `- 8 1/2 < - 1/2 - 4x ≤ 7 1/2`
⇒ `- 17/2 < - 1/2 - 4x ≤ 15/2`
Solving L.H.S. of the inequation,
⇒ `- 17/2 < - 1/2 - 4x`
⇒ `4x < 17/2 - 1/2`
⇒ `4x < 16/2`
⇒ 4x < 8
⇒ `x < 8/4`
⇒ x < 2 ...(1)
Solving R.H.S. of the inequation,
⇒ `-1/2 - 4x ≤ 15/2`
⇒ `- 4x ≤ 15/2 + 1/2`
⇒ `- 4x ≤ 16/2`
⇒ – 4x ≤ 8
Dividing by –4 on both sides we get,
⇒ x ≥ –2 ...(As on dividing by negative number the sign reverses)
⇒ x ≥ –2 ...(2)
From (1) and (2) we get,
–2 ≤ x < 2
Since, x ∈ I
Hence, solution set = {–2, –1, 0, 1}.
Solution on the number line is:

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