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Question
Solve the given inequality for real x: 2(2x + 3) – 10 < 6 (x – 2)
Sum
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Solution
`2 (2x + 3) -10 <6 (x - 2)`
= 4x + 6 - 10 < 6x - 12
= 4x - 4 < 6x - 12
= -4 + 12 < 6x - 4x
= 8 < 2x
= 4 < x
Thus, all real numbers x, which are greater than or equal to 4, are the solutions of the given inequality.
Hence, the solution set of the given inequality is (4, ∞).
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