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Question
Solve the following system of equations:
`2/x + 3/y = 13`
`5/x - 4/y = -2`
Sum
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Solution
Given:
`2/x + 3/y = 13`
`5/x - 4/y = -2`
Step-wise calculation:
1. Let `u = 1/x` and `v = 1/y`, so the system becomes a linear system in u, v:
2u + 3v = 13 and 5u – 4v = –2
2. Eliminate v: multiply the first equation by 4 and the second by 3:
8u + 12v = 52
15u – 12v = –6
Add: 23u = 46
⇒ u = 2
3. Substitute u = 2 into 2u + 3v = 13:
4 + 3v = 13
⇒ 3v = 9
⇒ v = 3
4. Return to x, y:
`u = 1/x = 2`
⇒ `x = 1/2`
`v = 1/y = 3`
⇒ `y = 1/3`
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