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Question
Solve the following question using appropriate Euclid’s axiom:
In the following figure, we have AC = DC, CB = CE. Show that AB = DE.
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Solution
Given, AC = DC ...(i)
And C6 = CE ...(ii)
According to Euclid’s axiom, if equals are added to equals, then wholes are also equal.
So, on adding equation (i) and (ii), we get
AC + CB = DC + CE
⇒ AB = DE
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