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Question
Solve the following quadratic equation:
`x^2 - 3sqrt(5)x + 10 = 0`
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Solution
1. Identify the coefficients
Compare the given equation with the standard quadratic form ax2 + bx + c = 0.
a = 1
b = `-3sqrt(5)`
c = 10
2. Calculate the discriminant
The discriminant (D) determines the nature of the roots and is given by the formula:
D = b2 – 4ac
Substitute the values of a, b and c:
`D = (-3sqrt(5)^2) - 4(1)(10)`
D = (9 × 5) – 40
D = 45 – 40
D = 5
3. Apply quadratic formula
The quadratic formula used to find the roots is:
`x = (-b ± sqrt(D))/(2a)`
Substitute the values of b, D and a into the formula:
`x = (-(-3sqrt(5)) +- sqrt(5))/(2(1))`
`x = (3sqrt(5) +- sqrt(5))/(2)`
4. Simplify the roots
Separate the equation into two cases to find both individual values of x:
Case 1 (Addition):
`x = (3sqrt(5) + sqrt(5))/2`
= `(4sqrt(5))/2`
= `2sqrt(5)`
Case 2 (Subtraction):
`x = (3sqrt(5) - sqrt(5))/2`
= `(2sqrt(5))/2`
= `sqrt(5)`
