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Question
Solve the following quadratic equation:
a2b2x2 + b2x – a2x – 1 = 0
Sum
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Solution
Given:
a2b2x2 + b2x – a2x – 1 = 0
⇒ b2x(a2x + 1) – 1(a2x + 1) = 0
⇒ (b2x – 1)(a2x + 1) = 0
⇒ (b2x – 1) = 0 or (a2x + 1) = 0
⇒ `x = 1/b^2` or `x = (-1)/a^2`
Hence, `1/b^2` and `(-1)/a^2` are the roots of the given equation.
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