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Maharashtra State BoardSSC (English Medium) 10th Standard

Solve the following quadratic equation. 5m2 + 2m + 1 = 0 - Algebra Mathematics 1

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Question

Solve the following quadratic equation.

5m2 + 2m + 1 = 0

Sum
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Solution

5m2 + 2m + 1 = 0

a = 5, b = 2, c = 1

= b2 - 4ac

= 4 - 4 × 5 × 1

= 4 - 20

= -16

∴ The roots of the quadratic equation are not real.

m = `(-"b" ± sqrt("b"^2 - 4"ac"))/"2a"`

= `(-2 ± sqrt((2)^2 - 4 xx 5 xx 1))/(2 xx 5)`

= `(-2 ± sqrt(4 - 20))/10`

= `(-2 ± sqrt(-16))/10`

= `(-2 + 4 sqrt-1)/10`

= `(2(-1 + 2 sqrt-1))/10`

= `(-1 -2 sqrt1)/5`

So, the roots are not real as the discriminant is negative.

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Chapter 2: Quadratic Equations - Problem Set 2 [Page 54]

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Balbharati Algebra (Mathematics 1) [English] Standard 10 Maharashtra State Board
Chapter 2 Quadratic Equations
Problem Set 2 | Q 7.5 | Page 54
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