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Question
Solve the following problem.
A metro train runs from station A to B to C. It takes 4 minutes in travelling from station A to station B. The train halts at station B for 20 s. Then it starts at station B and reaches station C in next 3 minutes. At the start, the train accelerates for 10 sec to reach a constant speed of 72 km/hr. The train moving at the constant speed is brought to rest in 10 sec. At the next station.
(i) Plot the velocity- time graph for the train travelling from station A to B to C.
(ii) Calculate the distance between the stations A, B and C.
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Solution

The metro train travels from station A to station B in 4 minutes = 240 s.
The trains halts at station B for 20 s.
The train travels from station B' to station C in 3 minutes = 180 s.
∴ Total time taken by the metro train in travelling from station A to B to C
= 240 + 20 + 180 = 440 s.
At the start, the train accelerates for 10 seconds to reach a constant speed of 72 km/hr = 20 m/s.
The train moving is brought to rest in 10s at the next station.
The velocity-time graph for the train travelling from station A to B to C is as follows:
Distance travelled by the train from station A to station B
= Area of PQRS
= A(Δ PQQ') + A(`square` Q'QRR') + A(SRR')
`= (1/2 xx 10xx20) + (220 xx 20) + (1/2 xx 10 xx 20)`
= 100 + 4400 + 100
= 4600 m
= 4.6 km
∴ Distance travelled by the train from station B' to station C
= Area of EFGD
= A(ΔEFF') + A(`square` F'FGG') + A(Δ DGG')
`= (1/2 xx 10 xx 20) xx (160 xx 20) + (1/2 xx 10 xx 20)`
= 100 + 3200 + 100
= 3400 m
= 3.4 km
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