English

Solve the following problem. A certain sound wave in air has a speed 340 m/s and wavelength 1.7 m for this wave, calculate the frequency the period

Advertisements
Advertisements

Question

Solve the following problem.

A certain sound wave in air has a speed 340 m/s and wavelength 1.7 m for this wave, calculate 

  1. the frequency
  2. the period
Sum
Advertisements

Solution

Given: v = 340 m/s, λ = 1.7 m

To find: frequency (n), period (T)

Formulae:

  1. n = `"v"/lambda`
  2. T = `1/"n"`

Calculation: From formula (i),

n = `340/1.7`

∴ n = 200 Hz

From formula (ii),

T = `1/200 = 1/(2 xx 10^2)`

= 5 × 10-3  ....(using reciprocal table)

∴ T = 0.005 s

The frequency of the sound wave is 200 Hz and its period is 0.005 s.

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Sound - Exercises [Page 158]

APPEARS IN

Balbharati Physics [English] Standard 11 Maharashtra State Board
Chapter 8 Sound
Exercises | Q 3. (i) | Page 158

RELATED QUESTIONS

Answer briefly.

Wave motion is doubly periodic. Explain.


Answer briefly.

Define amplitude.


Answer briefly.

Define wavelength of a wave.


Answer briefly.

Draw a wave and indicate points which are

  1. in phase
  2. out of phase
  3. have a phase difference of `pi/2`

Answer briefly.

Explain what is meant by phase of a wave.


Define progressive wave.


State any four properties of progressive wave.


Sound wave A has period 0.015 s, sound wave B has a period of 0.025 s. Which sound has greater frequency?


Two waves of the same amplitude superimpose to produce two beats per second. What is the ratio of minimum loudness to that of one of the waves?


The ratio of minimum to maximum wavelength in Balmer series is ____________.


Sound waves are passing through two routes one in straight path and the other along a semicircular path of radius r and are again combined into one pipe and superposed as shown in the figure. If the velocity of sound waves in the pipe is v, then frequencies of resultant waves of maximum amplitude will be integral multiples of ______.


In frequency modulated wave ______.


The frequency of a tuning fork is 384 per second and velocity of sound in air is 352 m/s. How far the sound has traversed while fork completes 48 vibration?


The wave of the wavelength 30 cm and frequency 100 Hz will be ______.


When the kinetic energy of an electron is increased, the wavelength of the associated wave will ______.


If velocity of sound in a gas is 360 m/s and the distance between a compression and the nearest rarefaction is 2 m, then the frequency of sound is ____________.


In a closed pipe, the note of fundamental frequency can be produced if the length of the air column is equal to ____________.


The frequency of a tuning fork is 220 Hz and the velocity of sound in air is 330 m/s. When the tuning fork completes 80 vibrations, the distance travelled by the ______.


A progressive wave of frequency 50 Hz is travelling with velocity 350 m/s through a medium. The change in phase at a given time interval of 0.01 s is ______.


When the observer moves towards a stationary source with velocity V1, the apparent frequency of emitted note is F1. When observer moves away from the source with velocity V1, the apparent frequency is F2. If V is the velocity of sound in air and `"F"_1/"F"_2=2` then `"V"/"V"_1` is equal to ______.


The wavelength of two waves are 50 and 51 cm respectively. If the temperature of the room is 20°C then what will be the number of beats produced per second by these waves, when the speed of sound at 0°C is 332 m/s?


A progressive wave of frequency 500 Hz is travelling with a velocity of 360 m/s. How far apart are two points 60° out of phase?


Wave of frequency 500 Hz has a phase velocity 360 ms-1. The phase difference between two displacement at a certain point at time 10-3 s apart will be ______.


The energy of photon corresponding to a radiation of wavelength 600 nm is 3.32 × 10−19 J. The energy of a photon corresponding to a wavelength of 400 nm is ______. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×