Advertisements
Advertisements
Question
Solve the following numerical problem.
The body temperature of a patient on Monday was102 °F and on Tuesday it was 104°F. What was the rise in temperature during these two days?
Advertisements
Solution
Body temperature on Monday = 102°F
Body temperature on Tuesday = 104°F
Rise in temperature = 104 — 102°F 2°F
APPEARS IN
RELATED QUESTIONS
Fill in the blank
Distance travelled d = ________ × time t
Match the following:
| Column A | Column B |
| 1.Volume of a liquid | 1. kg `m^-3` |
| 2. Area of a leaf | 2. `m^3` |
| 3. S.I. unit of volume | 3. graph paper |
| 4. S.I. unit of density | 4. m `s^-1` |
| 5. S.I.unit of speed | 5. measuring cylinder |
State two characteristics of a unit.
Convert the following quantity as indicated:
0.01 kg = ………. g
Answer the following in detail.
What are the fundamental physical quantities? Name any three fundamental physical quantities.
Answer the following in detail.
Explain in detail why railways and airlines use the 24-hour clock format.
Solve the following numerical problem.
20 one – rupee coins are placed one above the other. If their total height is 32 mm, find the thickness of one coin.
Physical quantities are classified into ______ type.
What are the multiples and sub multiples of mass?
A physical quantity A is dependent on other four physical quantities p, q, r and s as given below A = `sqrt("pq"/("r"^2"s"^3))`. The percentage error of measurement in p, q, r and s are 1%, 3%, 0.5% and 0.33% respectively, then the maximum percentage error in A is ______ %.
