Advertisements
Advertisements
Question
Solve the following equation by factorisation :
x(x + 1) + (x + 2)(x + 3) = 42
Advertisements
Solution
x(x + 1) + (x + 2)(x + 3) = 42
⇒ 2x2 + 6x + 6 – 42 = 0
⇒ x2 + 3x – 18 = 0
⇒ x2 + 3x – 18 = 0 ..(Dividing by 2)
⇒ x2 + 6x – 3x – 18 = 0
⇒ x(x + 6) 3(x + 6) = 0
⇒ (x + 6)(x – 3) = 0
Either x + 6 = 0,
then x = –6
or
x – 3 = 0,
then x = 3
Hence x = –6, 3.
APPEARS IN
RELATED QUESTIONS
Solve for x : `(x+1)/(x-1)+(x-1)/(x+2)=4-(2x+3)/(x-2);x!=1,-2,2`
`x^2-4x+1=0`
Solve the following quadratic equations by factorization:
\[9x^2 - 6 b^2 x - \left(a^4 - b^4 \right) = 0\]
Is there any real value of 'a' for which the equation x2 + 2x + (a2 + 1) = 0 has real roots?
Solve the following equation: `"x"^2 - ( sqrt 2 + 1) "x" + sqrt 2 = 0 `
Solve the following equation:
`(x - 1)/(2x + 1) + (2x + 1)/(x - 1) = 5/2 , x ≠-1/2`
Solve the following quadratic equation using formula method only
x2 - 6x + 4 = 0
A two digit number is such that the product of its digit is 8. When 18 is subtracted from the number, the digits interchange its place. Find the numbers.
The hypotenuse of a grassy land in the shape of a right triangle is 1 m more than twice the shortest side. If the third side is 7m more than the shortest side, find the sides of the grassy land.
At present Asha’s age (in years) is 2 more than the square of her daughter Nisha’s age. When Nisha grows to her mother’s present age, Asha’s age would be one year less than 10 times the present age of Nisha. Find the present ages of both Asha and Nisha.
