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Question
Solve the following equation: 3z – 18 = z – (12 - 4z)
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Solution
3z – 18 = z – (12 - 4z)
⇒ 3z - 18 = z - 12 + 4z
⇒ 3z - 18 = 5z - 12
⇒ 3z - 18 + 18 = 5z - 12 + 18 ...(Adding 18 to both sides)
⇒ 3z = 5z + 6
⇒ 3z - 5z = 5z + 6 - 5z (Subtracting 5z from both sides)
⇒ - 2z = 6
⇒ `(-2z)/(-2) = 6/-2` ...(Dividing by -2)
∴ z = - 3
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