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Question
Solve the following.
Calculate the pressure in atm of 1.0 mole of helium in a 2.0 dm3 container at 20.0°C.
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Solution
Given:
n = number of moles = 1.0 mol,
V = volume = 2.0 dm3
T = Temperature = 20.0°C = 20.0 + 273.15 K = 293.15 K
R = 0.0821 L atm K–1 mol–1
To find: Pressure (P)
Formula: PV = nRT
Calculation:
According to ideal gas equation,
PV = nRT
∴ P = `"nRT"/"V"`
∴ P = `(1.0xx0.0821xx293.15)/2.0`
∴ P = 12.03 atm
The pressure of the given helium gas is 12.03 atm.
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