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Solve the following. At 25 °C and 760 mm of Hg pressure, a gas occupies 600 mL volume. What will be its pressure at the height where the temperature is 10 °C and the volume of the gas 640 mL?

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Question

Solve the following.

At 25°C and 760 mm of Hg pressure, a gas occupies 600 mL volume. What will be its pressure at the height where the temperature is 10°C and the volume of the gas 640 mL?

Numerical
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Solution

Given:
V1 = Initial volume = 600 mL,
V2 = Final volume = 640 mL
P1 = Initial pressure = 760 mm Hg
T1 = Initial temperature = 25°C = 25 + 273.15 K = 298.15 K
T2 = Final temperature = 10°C = 10 + 273.15 K = 283.15 K

To find: P2 = Final pressure

Formula: `("P"_1"V"_1)/"T"_1=("P"_2"V"_2)/"T"_2`

Calculation:

According to combined gas law,

`("P"_1"V"_1)/"T"_1=("P"_2"V"_2)/"T"_2`

∴ `P_2 = ("P"_1"V"_1"T"_2)/("T"_1"V"_2)`

∴ `P_2 =(760xx600xx283.15)/(298.15xx640)`

∴ P2 = 676.654 mm Hg

The final pressure of a gas is 676.654 mm Hg.

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Chapter 10: States of Matter - Exercises [Page 159]

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Balbharati Chemistry [English] Standard 11 Maharashtra State Board
Chapter 10 States of Matter
Exercises | Q 5. (H) | Page 159

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