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Question
Solve the following assignment problem for minimization:
| Men | Tasks (in hours) | |||
| I | II | III | IV | |
| A | 7 | 25 | 26 | 10 |
| B | 12 | 27 | 3 | 25 |
| C | 37 | 18 | 17 | 14 |
| D | 18 | 25 | 23 | 9 |
Sum
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Solution
Minimum-time assignment (hours):
- A → Task I = 7
- B → Task III = 3
- C → Task II = 18
- D → Task IV = 9
Minimum total time = 7 + 3 + 18 + 9 = 37 hours
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2025-2026 (March) Board Question Paper
