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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Solve that abcabcabc|x+abcax+bcabx+c| = 0 - Mathematics

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Question

Solve that `|(x + "a", "b", "c"),("a", x + "b", "c"),("a", "b", x + "c")|` = 0

Sum
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Solution

`|(x + "a", "b", "c"),("a", x + "b", "c"),("a", "b", x + "c")|` = 0

Put x = 0

`|(0 + "a", "b", "c"),("a", 0 + "b", "c"),("a", "b", 0 + "c")|` = 0

`|("a", "b", "c"),("a", "b", "c"),("a", "b", "c")|` = 0

= 0

x = 0 satisfies the given equation. x = 0 is a root of the given equation

Since three rows are identical. x = 0 is a root of multiplicity 2.

Since the degree of the product of the leading diagonal elements (x + a)(x + b)(x + c) is 3.

There is one more root for the given equation.

Put x = – (a + b + c)

`|((-"a" + "b" + "c") + "a", "b", "c"),("a", -("a" + "b" + "c") + "b", "c"),("a", "b", -("a" + "b" + "c") + "c")|` = 0

`|(-"b" - "c", "b", "c"),("a", -"a" - "c", "c"),("a", "b", -"a" - "b")|` = 0

`"C"_1 -> "C"_1 + "C"_2 + "C"_3`

`|(-"b" - "c" + "b" + "c", "b", "c"),("a" - "a" - "c" + "c", -"a" - "c", "c"),("a" + "b" - "a" - "b", "b", -"a" - "b")|` = 0

`|(0, "b", "c"),(0, -"a" - "c", "c"),(0, "b", -"a" - "b")|` = 0

0 = 0

∴ x = – (a + b + c) satisfies the given equation.

Hence, the required roots of the given equation are x = 0, 0, – (a + b + c)

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Chapter 7: Matrices and Determinants - Exercise 7.3 [Page 34]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 7 Matrices and Determinants
Exercise 7.3 | Q 3 | Page 34

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