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Solve numerical example. Calculate the electric field due to a charge of −8.0×10−8 C at a distance of 5.0 cm from it. - Physics

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Question

Solve numerical example.

Calculate the electric field due to a charge of −8.0×10−8 C at a distance of 5.0 cm from it.

Sum
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Solution

Given: q = −8.0×10−8 C, r = 5 cm = 5 × 10−2 m

To find: Electric field (E)

Formula: E = `1/(4πε_0)"q"/"r"^2`

Calculation: From formula,

E = `9xx10^9xx((-8xx10^-8))/(5xx10^-2)^2`

= −2.88 × 105 N/C

Electric field due to a charge is −2.88 × 105 N/C.

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Chapter 10: Electrostatics - Exercises [Page 206]

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Balbharati Physics [English] Standard 11 Maharashtra State Board
Chapter 10 Electrostatics
Exercises | Q 3. (viii) | Page 206
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