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Question
Solve for x and y:
`2x + 3y + 1 = 0, (7 - 4x)/3 = y`
Sum
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Solution
The given equations are:
`(7 - 4x)/3 = y`
⇒ 4x + 3y = 7 ...(i)
And 2x + 3y + 1 = 0
⇒ 2x + 3y = –1 ...(ii)
On subtracting (ii) from (i), we get:
2x = 8
⇒ x = 4
On substituting x = 4 in (i), we get:
16x + 3y = 7
⇒ 3y = (7 – 16)
⇒ 3y = –9
⇒ y = –3
Hence, the solution is x = 4 and y = –3.
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