Question

Solve the following systems of equations:

`sqrt2x + sqrt3y = 0`

`sqrt3x - sqrt8y = 0`

Answer 1

`sqrt2x + sqrt3y = 0`....(i)

`sqrt3x - sqrt8y = 0` ....(ii)

From equation (i), we obtain:

`x = (-3sqrty)/sqrt2` ....(iii)

Substituting this value in equation (ii), we obtain:

`sqrt3 ((- sqrt3y)/sqrt2) - sqrt8y = 0`

`- (3y)/sqrt2 - 2sqrt2y = 0`

`y (-3/sqrt2 - 2sqrt2) = 0`

y = 0

Substituting the value of y in equation (iii), we obtain:

x= 0

`:. x = 0, y = 0`