Advertisements
Advertisements
Question
Solve the following equation: 3x2 + 25 x + 42 = 0
Advertisements
Solution
3x2 + 25 x + 42 = 0
`"x"^2 + 25/3 "x" + 14 = 0`
`"x"^2 + 6"x" + 7/3 "x" + 14 = 0`
`"x"("x" + 6) + 7/3 ("x" + 6) = 0`
`("x" + 6)("x" + 7/3) = 0`
(x + 6) = 0 , `("x" + 7/3) = 0`
x = -6 , x = `-7/3`
APPEARS IN
RELATED QUESTIONS
Solve the following quadratic equations by factorization:
4x2 + 4bx - (a2 - b2) = 0
Solve the following quadratic equations by factorization:
`(x-1)/(2x+1)+(2x+1)/(x-1)=5/2` , x ≠ -1/2, 1
The sum of the squares two consecutive multiples of 7 is 1225. Find the multiples.
Solve the following equation: `("x" + 3)/("x" - 2) - (1 - "x")/"x" = 17/4`
Solve the following quadratic equation by factorisation:
9x2 - 3x - 2 = 0
Solve the following quadratic equation by factorisation method:
`x/(x + 1) + (x + 1)/x = (34)/(15') x ≠ 0, x ≠ -1`
Solve: x(x + 1) (x + 3) (x + 4) = 180.
In each of the following determine whether the given values are solutions of the equation or not.
x2 + x + 1 = 0; x = 1, x = -1.
Find two consecutive even natural numbers such that the sum of their squares is 340.
The lengths of the parallel sides of a trapezium are (x + 9) cm and (2x – 3) cm and the distance between them is (x + 4) cm. If its area is 540 cm2, find x.
