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Solve the Following Determinant Equation: ∣ ∣ ∣ ∣ X + a B C a X + B C a B X + C ∣ ∣ ∣ ∣ = 0

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Question

​Solve the following determinant equation:

\[\begin{vmatrix}x + a & b & c \\ a & x + b & c \\ a & b & x + c\end{vmatrix} = 0\]

 

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Solution

\[\text{ Let }∆ = \begin{vmatrix}x + a & b & c \\ a & x + b & c \\ a & b & x + c\end{vmatrix}\] 

\[ = \begin{vmatrix}x + a + b + c & b & c \\ x + a + b + c & x + b & c \\ x + a + b + c & b & x + c\end{vmatrix} \left[\text{ Applying }C_1 \text{ to }C_1 + C_2 + C_3 \right]\] 

\[ = \left( x + a + b + c \right)\begin{vmatrix}1 & b & c \\ 1 & x + b & c \\ 1 & b & x + c\end{vmatrix} \] 

\[ = \left( x + a + b + c \right)\begin{vmatrix}1 & b & c \\ 0 & x & 0 \\ 1 & b & x + c\end{vmatrix} \left[\text{ Applying }R_2 \text{ to }R_2 - R_1 \right]\] 

\[ = \left( x + a + b + c \right)\begin{vmatrix}1 & b & c \\ 0 & x & 0 \\ 0 & 0 & x\end{vmatrix} \left[\text{ Applying }R_3 \text{ to }R_3 - R_1 \right]\] 

\[ ∆ = \left( x + a + b + c \right)\left( x^2 - 0 \right) = 0 \left[\text{ Given }\right]\] 

\[ \Rightarrow x^2 = 0\text{ or }x + a + b + c = 0\] 

\[ \Rightarrow x = 0\text{ or }x = - \left( a + b + c \right)\]

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Chapter 5: Determinants - Exercise 6.2 [Page 61]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 5 Determinants
Exercise 6.2 | Q 52.1 | Page 61

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