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Question
Solve each of the following Cryptarithm:
1 2 A
+ 6 A B
A 0 9
Sum
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Solution
\[A + B = 9 \text{ as the sum of two digits can never be }19\]
\[2 + A = 0, A\text{ must be
}8\]
\[A + B = 9, 8 + B = 9, B = 1\]
\[\text{ So, } A = 8, B = 1\]
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