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Question
Solve: `(3x)/5 + 2 < x+4<= x/2 + 5, x ∈ R` and represent the solution set on the number line.
Sum
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Solution
1) `(3x)/5 + 2 < x + 4 (3x)/5 + 2 < x + 4 `
⇒ `2 - 4 < x - (3x)/5 = (2x)/5`
⇒ `-2 < (2x)/5`
⇒ −10 < 2x
⇒ x > −5
2) `x + 4 ≤ x/2 + 5 x - x/2 ≤ 5 - 4 (1/2)x ≤ 1 x ≤ 2`
Combine: x > −5 and x ≤ 2
−5 < x ≤ 2

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