Question

Slope of the straight line obtained by plotting log₁₀k against represents what term?

Options

• −E_a

• `(-2.303  "E"_"a")/"R"`

• `(-"E"_"a")/(2.303  "R")`

• `(-"E"_"a")/"R"`

Answer 1

`\bb((-"E"_"a")/(2.303  "R"))`

Explanation:

According to Arrhenius equation,

K = `"Ae"^((-"E"_"a")//"RT")`

ln k = `ln"A" - "E"_"a"/"RT"`

log k = `log "A" - "E"_"a"/(2.303  "R") xx 1/"T"`

y = mx + C

y = log k; x = `1/"T"`; Slope = `(-"E"_"a")/(2.303  "R")`

m = `(-"E"_"a")/(2.303  "R")`