Question

`((sin^2 23^circ + sin^2 67^circ))/((cos^2 13^circ + cos^2 77^circ)) + sin^2 59^circ + cos 59^circ sin 21^circ` = ?

Options

• 3

• 2

• 1

• 0

Answer 1

2

Explanation:

Given expression = `(sin^2 23^circ + sin^2 (90^circ - 23^circ))/(cos^2 13^circ + cos^2 (90^circ - 13^circ)) + sin^2 59^circ + cos 59^circ sin (90^circ - 59^circ)`

= `(sin^2 23^circ + cos^2 23^circ)/(cos^2 13^circ + sin^2 13^circ) + (sin^2 59^circ + cos^2 59^circ)`

= 1 + 1

= 2