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Simplify: (๐‘ฅ^๐‘Ž/๐‘ฅ^๐‘)^๐‘Ž+๐‘โข (๐‘ฅ^๐‘/๐‘ฅ^๐‘)^๐‘+๐‘โข (๐‘ฅ^๐‘/๐‘ฅ^๐‘Ž)^๐‘+๐‘Ž - Mathematics

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Question

Simplify:

`(x^a/x^b)^(a + b) (x^b/x^c)^(b + c) (x^c/x^a)^(c + a)`

Simplify
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Solution

The given expression is `(x^a/x^b)^(a + b) (x^b/x^c)^(b + c) (x^c/x^a)^(c + a)`

= `(x^(a - b))^(a + b) (x^(b - c))^(b + c) (x^(c - a))^(c + a)`  ...`(โˆต a^m/a^n = a^(m - n))`

= `x^((a + b)(a - b)) x^((b - c)(b + c)) x^((c - a)(c + a))`  ...(โˆต (am)n = amn)

= `x^(a^2 - b^2) x^(b^2 - c^2)x^(c^2 - a^2)`

= `x^(a^2 - b^2 + b^2 - c^2 + c^2 - a^2)`  ...(โˆต am × an = am + n)

= x

= 1

Hence the required is 1.

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Chapter 6: Indices - EXERCISE 6 [Page 67]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
EXERCISE 6 | Q 9. (ii) | Page 67
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