English

Simplify: ๐‘ฅ^๐‘Ž+๐‘ โ‹… ๐‘ฅ^๐‘+๐‘ โ‹… ๐‘ฅ^๐‘+๐‘Ž/(๐‘ฅ^๐‘Ž โ‹… ๐‘ฅ^๐‘ โ‹… ๐‘ฅ^๐‘)^2 - Mathematics

Advertisements
Advertisements

Question

Simplify:

`(x^(a + b) * x^(b + c) * x^(c + a))/(x^a * x^b * x^c)^2`

Simplify
Advertisements

Solution

`(x^(a + b) * x^(b + c) * x^(c + a))/(x^a * x^b * x^c)^2`

Thus, we have

⇒ `x^(a + b + b + c + c + a)/(x^(2a) * x^(2b) * x^(2c))`  ...[โˆต (an)m = anm]

⇒ `x^(2a + 2b + 2c)/x^(2a + 2b + 2c)`  ...[โˆต an × am = an + m]

⇒ 1

Hence, the required is 1.

shaalaa.com
  Is there an error in this question or solution?
Chapter 6: Indices - EXERCISE 6 [Page 67]

APPEARS IN

B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
EXERCISE 6 | Q 9. (iii) | Page 67
Share
Notifications

Englishเคนเคฟเค‚เคฆเฅ€เคฎเคฐเคพเค เฅ€


      Forgot password?
Use app×