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Simplify the following: (2x + 5y)^3 – (2x – 5y)^3 - Mathematics

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Question

Simplify the following:

(2x + 5y)3 – (2x – 5y)3

Simplify
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Solution

Step 1: Expand the first term

We expand the first term (2x + 5y)3 using the binomial formula (a + b)3 = a3 + 3a2b + 3ab2 + b3:

(2x + 5y)3 = (2x)3 + 3(2x)2(5y) + 3(2x)(5y)2 + (5y)3

(2x + 5y)3 = 8x3 + 3(4x2)(5y) + 3(2x)(25y2) + 125y3

(2x + 5y)3 = 8x3 + 60x2y + 150xy2 + 125y3

Step 2: Expand the second term

We expand the second term (2x – 5y)using the binomial formula (a – b)3 = a3 – 3a2b + 3ab2 – b3:

(2x – 5y)3 = (2x)3 – 3(2x)2(5y) + 3(2x)(5y)2 – (5y)3

(2x – 5y)3 = 8x3 – 3(4x2)(5y) + 3(2x)(25y2) – 125y3

(2x – 5y)3 = 8x3 – 60x2y + 150xy2 – 125y3

Step 3: Subtract the expanded terms

Subtract the expanded second term from the first term:

(2x + 5y)3 – (2x – 5y)3

= (8x3 + 60x2y + 150xy2 + 125y3) – (8x3 – 60x2y + 150xy2 – 125y3)

= 8x3 + 60x2y + 150xy2 + 125y3 – 8x3 + 60x2y – 150xy2 + 125y3

Step 4: Combine like terms

Group and combine the like terms:

= (8x3 – 8x3) + (60x2y + 60x2y) + (150xy2 – 150xy2) + (125y3 + 125y3)

= 0 + 120x2y + 0 + 250y3

= 120x2y + 250y3

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Chapter 3: Expansions - Exercise 3A [Page 64]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 3 Expansions
Exercise 3A | Q 9. (iv) | Page 64
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