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Question
Simplify the following:
(2x + 5y)3 – (2x – 5y)3
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Solution
Step 1: Expand the first term
We expand the first term (2x + 5y)3 using the binomial formula (a + b)3 = a3 + 3a2b + 3ab2 + b3:
(2x + 5y)3 = (2x)3 + 3(2x)2(5y) + 3(2x)(5y)2 + (5y)3
(2x + 5y)3 = 8x3 + 3(4x2)(5y) + 3(2x)(25y2) + 125y3
(2x + 5y)3 = 8x3 + 60x2y + 150xy2 + 125y3
We expand the second term (2x – 5y)3 using the binomial formula (a – b)3 = a3 – 3a2b + 3ab2 – b3:
(2x – 5y)3 = (2x)3 – 3(2x)2(5y) + 3(2x)(5y)2 – (5y)3
(2x – 5y)3 = 8x3 – 3(4x2)(5y) + 3(2x)(25y2) – 125y3
(2x – 5y)3 = 8x3 – 60x2y + 150xy2 – 125y3
Step 3: Subtract the expanded terms
Subtract the expanded second term from the first term:
(2x + 5y)3 – (2x – 5y)3
= (8x3 + 60x2y + 150xy2 + 125y3) – (8x3 – 60x2y + 150xy2 – 125y3)
= 8x3 + 60x2y + 150xy2 + 125y3 – 8x3 + 60x2y – 150xy2 + 125y3
Group and combine the like terms:
= (8x3 – 8x3) + (60x2y + 60x2y) + (150xy2 – 150xy2) + (125y3 + 125y3)
= 0 + 120x2y + 0 + 250y3
= 120x2y + 250y3
