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Question
Simplify:
\[4\frac{4}{5} \div \frac{3}{5} \text{ of } 5 + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5}\]
Sum
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Solution
Given expression:
\[= 4\frac{4}{5} \div \frac{3}{5} \text{of} 5 + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5}\]
\[ = 4\frac{4}{5} \div \frac{3}{5} \times \frac{5}{1} + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5} (\text{Removing 'of '})\]
\[ = \frac{24}{5} \div \frac{3}{1} + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5} \]
\[ = \frac{24}{5} \times \frac{1}{3} + \frac{4}{5}\times \frac{3}{10} - \frac{1}{5} (\text{Removing } '\div')\]
\[ = \frac{8}{5} + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5} (\text{Removing } ' \times ')\]
\[ = \frac{8}{5} + \frac{6}{25} - \frac{1}{5} (\text{Removing } ' \times ')\]
\[ = \frac{40 + 6 - 5}{25} = \frac{41}{25} = 1\frac{16}{25}\]
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