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Simplify: (๐‘ฅ^๐‘Ž+๐‘)^3 โ‹… (๐‘ฅ^๐‘+๐‘)^3 โ‹… (๐‘ฅ^๐‘+๐‘Ž)^3/(๐‘ฅ^๐‘Žโข๐‘ฅ^๐‘โข๐‘ฅ^๐‘)^6 - Mathematics

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Question

Simplify:

`((x^(a + b))^3 * (x^(b + c))^3 * (x^(c + a))^3)/((x^a x ^b x^c)^6`

Simplify
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Solution

We are asked to simplify:

`((x^(a + b))^3 * (x^(b + c))^3 * (x^(c + a))^3)/((x^a * x ^b * x^c)^6`

Step 1: Expand numerator

`(x^(a + b))^3 = x^(3(a + b))`,

`(x^(b + c))^3 = x^(3(b + c))`,

`(x^(c + a))^3 = x^(3(c + a))`

So numerator:

`x^(3(a + b)) * x^(3(b + c)) * x^(3(c + a)) = x^((3(a + b) + 3(b + c) + 3(c + a)`

Simplify exponents:

3a + 3b + 3b + 3c + 3c + 3a = 6a + 6b + 6c

So numerator = `x^(6a + 6b + 6c)`

Step 2: Expand denominator

`(x^a * x^b * x^c)^6 = (x^(a + b + c))^6`

= `x^(6(a + b + c))`

= `x^(6a + 6b + 6c)`

Step 3: Simplify fraction

`x^(6a + 6b + 6c)/(x^(6a + 6b + 6c)) = x^0 = 1`

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Chapter 6: Indices - MISCELLANEOUS EXERCISE [Page 69]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
MISCELLANEOUS EXERCISE | Q 1. (v) | Page 69
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