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Simplify: (27โข๐‘Ž^9)^โˆ’1/3 โข(64โข๐‘Ž^15)^2/3 - Mathematics

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Question

Simplify:

`(27a^9)^((-1)/3) (64a^15)^(2/3)`

Simplify
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Solution

Let’s simplify the expression:

`(27a^9)^(-1/3) * (64a^15)^(2/3)`

Step 1: Apply the power rule: `(x^m)^n = x^(mn)`

`(27a^9)^(-1/3) = 27^(-1/3) * a^(9*(-1/3))`

= `3^(-3 * 1/3) * a^-3`

= `3^-1 * a^-3`

`(64a^15)^(2/3) = 64^(2/3) * a^(15 * 2/3)`

= `4^2 * a^10`

= `16a^10`

Step 2: Multiply the simplified parts:

`3^-1 * a^-3 * 16a^10`

= `1/3 * 16 * a^(-3 + 10)`

= `16/3 a^7`

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Chapter 6: Indices - MISCELLANEOUS EXERCISE [Page 69]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
MISCELLANEOUS EXERCISE | Q 3. (ii) | Page 69
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